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right)^2 - c\) which can then be solved by taking the square root of both sides. Start by following the formula ... right)^2 + c\) For this example, this gives: \(\left(x + \frac{6}{ ...
It is not possible to find the square root of a negative number, so the equation has no solutions. The graph of \(y = x^2 + 2x + 5\) does not cross or touch the x-axis so the equation \(x^2 + 2x ...
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